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Velocity-Time Graphs — An Examiner's Guide

Reading acceleration from the gradient, distance from the area, and the four mistakes I see most often when marking GCSE papers.

By Fiaraz Iqbal — former Headteacher, AQA examiner, 30+ years teaching Maths in Yorkshire

Velocity-time graphs sit at the boundary between Maths and Physics — they appear on both syllabi, and the GCSE Maths Higher version is usually worth six to nine marks. The two skills you need are simple to state but easy to mix up: gradient gives acceleration; area under the graph gives distance. This guide walks through both, plus the worded scenarios that come up most often.

The two key facts

Gradient = acceleration
Area under the graph = distance travelled

That's the whole topic, distilled. Everything else is geometry.

Reading acceleration from the gradient

Pick two points on a straight section of the graph. Acceleration = change in velocity / change in time.

Worked example 1

A car accelerates from 0 m/s to 20 m/s in 8 seconds. Find its acceleration.

acceleration = (20 − 0) / (8 − 0) = 20 / 8 = 2.5 m/s²

If the line slopes downwards, the gradient is negative — that's deceleration (or "negative acceleration"). If the line is horizontal, the gradient is 0 — the object is moving at constant velocity (no acceleration).

Reading distance from the area

The distance travelled in any time interval equals the area under the graph in that interval. Break the area into rectangles, triangles and trapeziums.

Worked example 2

A cyclist accelerates from rest to 8 m/s over 4 seconds, holds that speed for 6 seconds, then decelerates to rest over 5 seconds. Find the total distance travelled.

The graph is a triangle, then a rectangle, then another triangle.

Triangle 1: ½ × 4 × 8 = 16 m

Rectangle: 6 × 8 = 48 m

Triangle 2: ½ × 5 × 8 = 20 m

Total distance = 16 + 48 + 20 = 84 m

The trapezium shortcut

Many velocity-time questions involve a trapezium-shaped region (object accelerates from one speed to another over some time). Use the trapezium area formula:

Area = ½ × (a + b) × h

Where a and b are the parallel sides (the two velocities) and h is the time.

Average speed across the whole journey

Average speed = total distance / total time

For the cyclist above: 84 / 15 = 5.6 m/s.

Examiner's note: "Average speed" is NOT the same as the average of the two end velocities. It's total distance over total time. Mixing this up costs a mark every paper.

Curved velocity-time graphs (Higher tier)

If the graph is curved instead of made of straight lines:

For more detail on these techniques, see gradients of curves and area under curves.

The mistakes that cost the most marks

Mistake 1 — Confusing distance and displacement. Area below the time axis would represent motion in the opposite direction. At GCSE you mostly stay above the axis, but be careful if a graph dips below.
Mistake 2 — Gradient errors with negative slopes. A negative gradient is deceleration. Don't drop the minus sign — examiners want to see −2.5 m/s², not 2.5.
Mistake 3 — Wrong units. Acceleration is m/s² (m per second per second). Velocity is m/s. Distance is m. A naked number with no unit usually loses one mark.
Mistake 4 — Treating average speed as the mean of two velocities. Use total distance ÷ total time. The mean of two velocities only works when the object spends equal times at each — almost never the case in exam questions.

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